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400x^2+864x-1440=0
a = 400; b = 864; c = -1440;
Δ = b2-4ac
Δ = 8642-4·400·(-1440)
Δ = 3050496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3050496}=\sqrt{9216*331}=\sqrt{9216}*\sqrt{331}=96\sqrt{331}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(864)-96\sqrt{331}}{2*400}=\frac{-864-96\sqrt{331}}{800} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(864)+96\sqrt{331}}{2*400}=\frac{-864+96\sqrt{331}}{800} $
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